feat: 车辆考核追踪sheet业务员名加部门前缀

考核明细和发放明细中的业务员统一显示为"X部-姓名"格式。

Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>

excel_writer.py

@@ -383,7 +383,8 @@ def write_vehicle_tracking_sheet(wb, settle_month, G, master_vehicles, vehicle_p
                     t=g['应考核']; a=g['实际']
                     cum_t+=t; cum_a+=a
                     q='达标' if g['有达标'] else '未达标'
-                    lines.append(f"{g['销售']}: {R(a,0)}/{R(t,0)} {q}")
+                    sd = g['部门'].replace('业务','') if '业务' in g.get('部门','') else g.get('部门','')
+                    lines.append(f"{sd}-{g['销售']}: {R(a,0)}/{R(t,0)} {q}")
                 row.append('\n'.join(lines))
             else:
                 row.append('')
@@ -397,7 +398,8 @@ def write_vehicle_tracking_sheet(wb, settle_month, G, master_vehicles, vehicle_p
         if tp:
             pay_lines = []
             for p in sorted(tp, key=lambda x: x['业务员']):
-                pay_lines.append(f"{p['业务员']}: {R(p['金额'])}({p['类型']})")
+                pd = p.get('部门','').replace('业务','') if '业务' in p.get('部门','') else p.get('部门','')
+                pay_lines.append(f"{pd}-{p['业务员']}: {R(p['金额'])}({p['类型']})")
             row.append('\n'.join(pay_lines))
         else:
             row.append('')